If a [OH-] = 5.0*10^-5 M , then pH will be

Dear Student,

H+ OH- = 1 ×10-14H+ 5 ×10-5 = 1 ×10-14H+ =  1 ×10-145 ×10-5  =  1 ×10-14×1055 =10×10-14×1045H+ =2 ×10-10pH = -logH+ = -log2 ×10-10= 10-log2pH = 9.66Regards

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