# if R=V+I and V=(100+_5)and I= (10+_2). what is the percentage error ​

Dear Student,
Here in this question voltage V =  and current , I =
Resistance R =
Now , $\frac{∆R}{R}=±\left(\frac{∆V}{V}+\frac{∆I}{I}\right)=±\left(\frac{5}{100}+\frac{2}{10}\right)=±0·25$
Therefore ,
Resistance with error limit , R =$\left(10±2·5\right)\Omega$
Percentage error in R =
Regards

• 0
the percentage is mostly about 6 % you may refer to the provided study material
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