if the 21st and 22nd terms in the expansion of (1+x)^44 are equal then find the value of x. Share with your friends Share 2 Shipra D. answered this The nth term of the binomial expansion 1+x44 is given as: Tn=Cn-144x44-n-11n-1⇒T21=C2044x44-21-1121-1=C2044x24 And ⇒T22=C2144x44-22-1122-1=C2144x23 Now, T21=T22⇒C2044x24=C2144x23⇒x=C2144C2044=44!21!23!44!20!24!=78 27 View Full Answer