If the child weighs 20kg and if the lift is
moving down with a uniform acceleration
of 5ms^ -2, what will be the apparent weight
of the child?

Dear student,

Given, a = 5m/s2

m = 20kg

Now weight = m g

apparent weight, w = m (g-a) N [because lift is moving downwards]

= 20 (9.8-5)

=96 N


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