If the value of C.F.S.E. for “Ni” is del0 then for Pd it should be​
a) 1.1 del0
b) 0.5 del0
c) 1.5 del0
d) 2 del0

Dear Student,
 
On going from 3d to 4d series, CFSE increases by 50%. 
Now, for Ni, CFSE=​Δo
So, For Pd, CFSE= â€‹Δo+0.50​Δo =1.5Δo

Hence, correct answer is (c)
 

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