if x is the degree of dissociation of K₄[Fe(CN_​6), then abnormal mass of complex in the solution will be

Given,
    Degree of dissociation of K₄[Fe(CN)₆] is x
The dissociation of K₄[Fe(CN)₆] can be depicted as follows:
         K₄[Fe(CN)₆] → 4K⁺ + [Fe(CN)₆]^4-
Van't hoff's factor, i = number of dissociated ions = 5
         We know that,
             Van't Hoff's factor, i = Normal Molar Mass / Abnormal Molar Mass
                                            5 = 368.35 / Abnormal Molar Mass
                   Abnormal Molar Mass = 368.35 / 5
                                                         = 73.67