I f log 10 x 3 + y 3 - log 10 x 2 - x y + y 2 + log 10 x 3 - y 3 - log 10 x 2 + x y + y 2 = log 10 221 w h e r e x , y a r e i n t e g e r s t h e n I f x = 111 t h e n y c a n b e ( A ) ± 111 B ± 2 C ± 110 D ± 109 I f y = 2 t h e n v a l u e o f x c a n b e ( A ) ± 111 B ± 15 C ± 2 D ± 110 Share with your friends Share 0 Neha Sethi answered this Dear student Given:log10x3+y3-log10x2-xy+y2+log10x3-y3-log10x2+xy+y2=log10221⇒log10x3+y3x2-xy+y2+log10x3-y3x2+xy+y2=log10221⇒log10x+yx2-xy+y2x2-xy+y2+log10x-yx2+xy+y2x2+xy+y2=log10221⇒log10x+y+log10x-y=log10221⇒log10x2-y2=log10221⇒x2-y2=221⇒x2-y2=221 and y2-x2=221Case I : x2-y2=221When x=111⇒1112-221=y2⇒y2=1112-221=±110Case I : y2-x2=221When x=111⇒y2=221+x2⇒y2=221+1112⇒y=±111 approx.Similarly try other part.Note:logamn=logam-loganlogamn=logam+logana3+b3=a+ba2-ab+b2a3-b3=a-ba2+ab+b2 For remaining queries we request you to post them in separate threads to have rapid assistance from our experts. Regards 0 View Full Answer