I f log 10 x 3 + y 3 - log 10 x 2 - x y + y 2 + log 10 x 3 + y 3 - log 10 x 2 - x y + y 2 = log 10 221 w h e r e x , y a r e i n t e g e r s , t h e n I f x = 111 t h e n y c a n b e A ) ± 111 B ) ± 2 C ) ± 110 D ) ± 109 I f y = 2 t h e n x c a n b e A ) ± 111 B ) ± 15 C ) ± 2 D ) ± 110 Share with your friends Share 0 Aarushi Mishra answered this log10x3+y3-log10x2+y2-xy+log10x3-y3-log10x2+y2+xy=log10 221Use logx a-logx b=logx ablog10x3+y3x2+y2-xy+log10x3-y3x2+y2+xy=log10 221Use x3+y3=x+yx2+y2-xy and x3-y3=x-yx2+y2+xylog10x+yx2+y2-xyx2+y2-xy+log10x-yx2+y2+xyx2+y2+xy=log10 221log10x+y+log10x-y=log10 221Use logam+logan=logamnlog10x+yx-y=log10 221log10x2-y2=log10 221Comapringx2-y2=221x2-y2=±221If x=1111112-y2=±2211112-y2=±221y2=12321±221y2=12321+221 or y2=12321-221y2=12542 or y2=12100y=±12542 or y=±12100y=±119.99 or y=±110 y=±110Option cNow if y=2x2-22=±221x2=4±221x2=4+221 or x2=4-221x2=225 or x2=-217x2=-217 has no real solutionsx=±225x=±15Option b 0 View Full Answer