In a bcc unit cell,if half of the atoms per unit cell are removed,then %age void is???
Number of atoms per unit cell in BCC lattice = 2
If half of the atoms are removed, number of remaining atoms per unit cell = 1
So % void space = 100 – 34 = 66%
In a bcc unit cell,if half of the atoms per unit cell are removed,then %age void is???
Number of atoms per unit cell in BCC lattice = 2
If half of the atoms are removed, number of remaining atoms per unit cell = 1
So % void space = 100 – 34 = 66%