# Kp for the reaction 2H2S gives 2H2 +S2 is 0.0118 at 1065 degree Celsius and heat of dissociation is 42.4kcal. find the equilibrium constant at 1132 degree Celsius.

1. Kp = Kc(RT)n2-n​1
2.   2H2$⇔$ 2H2 + S2

Kp = 0.0118 (8.314 $×$ 106.5)1 = 1.02

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