Well, In set A, the no. of terms are 3. And in the set there are a total of 2 terms.
n(A)=3 (let be p); n(B)=2(let be q);
therefore total number of relations that can be formed are 2p*q => 23*2 => 26 => 64 (not 128)
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Priya answered this
No. of subsets=2^(No. of elements of A * No. of elements in B)
No. of relation from A to B=No. of subsets of A*B
=2^(3 * 2 )
=64