Let ABC be a triangle and M be a point on side AC closer to vertex C than A. Let N be a point on side AB such that MN is parallel to BC and let P be a point on side BC such that MP is parallel to AB. If the area of the quadrilateral BNMP is equal to 5/18 th of the area of triangle ABC, then the ratio AM/MC equals :  (A) 5 (B) 6 (C)18/5 (D)15/2 . No links