NaBH4 + A at 450 K ----> B (electron deficient dimer) B + NH3 at 200°C ----> C 1 : 2 Incorrect statement about A, B & C is :- a) A is hypervalent compound b) B is non planar molecule c) C is an aromatic, non-polar molecule d) B gives H3BO3 on hydrolysis Also name A, B and C Share with your friends Share 8 Vartika Jain answered this Dear Student, B is an electron deficient dimer, therefore it is diborane i.e. B2H6. Reaction of NaBH4 with I2 yields B2H6, therefore, A is I2Now, B2H6 on reaction with NH3 gives borazine, so C is borazine i.e. B3N3H6or, NaBH4 + I2 → B2H6 (A) (B)B2H6 + NH3 → B3N3H6 (C)Now, I2 is not hypervalent, therefore (a) is incorrect and B3N3H6 is aromatic but the molecule is polar. Therefore, incorrect answer are (a) and (c) -1 View Full Answer
