Need proper and correct explanation. Share with your friends Share 0 Sanjay Singh answered this Dear student Let the time is measured when the particle is at its positive extreme position and distance is measured from the negative extreme position of SHM. Let position of particle be x=Asin(ωt+θ)at t=0 particle is lying that is x=+A at its negative extreme position A=Asin(ω×0+θ)sinθ=1θ=π2x=Asin(ωt+π2)=Acos(ωt) Distance of particle from the mean position at time t is x=Acos(ωt)So distance of particle from negative extreme position isX=A+x=A+Acos(ωt)Regards 58 View Full Answer Tanay Gupta answered this Should be 4 as take t=0 therefore distance =2A as it is measured b/ extreme posn 0
