normality of 2M sulphuric acid is....... explain

a) 2N

b) 4N

c) N/2

d) N/4

Equivalent weight (E) of sulphuric acid = molecular weight of sulphuric acid(M)/(1X2) = M/2
 
So, M = 2E
 
2M sulphuric acid means,
1L solution contains 2 M sulphuric acid
    = 2X(2E) Sulphuric acid
    = 4E Sulphuric acid = 4N Sulphuric acid
 
So answer is b) 4N