Osmotic pressure of a solution containing 3.5g of dissolved protein per 50 cc of a solution is 25 mm (Hg) at 37 0C . Calculate the molar mass of protein .

m2, Dissolved protein =3.5gVolume =50cc =50mL =0.05 Lπ, Osmotic Pressure =25mmHg or 25760atmTemperature =37oC =310KMolar mass of protein =?π=n2RTV or m2RTM2VR=gas constant =0.082 Latm/K/molM2 is the molar mass of soluteSubstituting the valuesM2=3.5×0.082×310×7600.05×25=54093.6 g/mol
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