Dear Student A car accelerates at rate f and than travels with constant speed for time t and than retards with accelerationf/2 Total distance=15Sas u=0ms-1v2-u2=2fSv=2fSv×t=S2v2=2f/2×S3s0 fS3=2fSS3=2SS2 becomes=12Svt=12S2fS×t=12S on solving S=2ft2144Hope this information will clear your doubts about topic If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible Regards

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A c a r a c c e l e r a t e s a t r a t e f a n d t h a n t r a v e l s w i t h c o n s \tan t s p e e d f o r t i m e t a n d t h a n r e t a r d s w i t h a c c e l e r a t i o n f / 2 . T o t a l d i s \tan c e = 15 S a s u = 0 m s^{- 1} v^{2} - u^{2} = 2 f S v = \sqrt{2 f S} v \times t = S_{2} v^{2} = 2 f / 2 \times S_{3} s 0 \sqrt{f S_{3}} = \sqrt{2 f S} S_{3} = 2 S S_{2} b e c o m e s = 12 S v t = 12 S \sqrt{2 f S} \times t = 12 S o n s o l v i n g S = \frac{2 f t^{2}}{144} H o p e t h i s i n f o r m a t i o n w i l l c l e a r y o u r d o u b t s a b o u t t o p i c . I f y o u h a v e a n y m o r e d o u b t s j u s t a s k h e r e o n t h e f o r u m a n d o u r e x p e r t s w i l l t r y t o h e l p y o u o u t a s s o o n a s p o s s i b l e . R e g a r d s

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