Please answer .with explaination

Dear Student 
Given: (V)Volume of solution =500ml       or    0.5 lt
           (n) Moles=0.01 moles of KCl + 0.03  moles of urea Total Moles= 0.04 moles
          R=0.0821atmlt/moleK
         (T)Temp=27⁰C             27+273=300K
        The formula for osmotic pressure
         ∏=nRT/V
        ∏=0.04 moles* 0.0821atmltMole^-1K^-1 *300K/ 0.5lt
       ∏=2atm
        

Regards