Please explain and answer immediately Please explain and answer immediately 3k. Decomposition of H202 follows a first order reaction. In fifty minutes the concentration of H202 decreases from 0.5 to 0.125 M in one such decomposition. When the concentration of H202 reaches 0.05 M, the rate of formation of 02 will be (b) 6.93 x lo- mol min- (a) 6.93 x 10- mol min- -1 (c) 2.66 L min-l at STP (d) 1.34 x 10- mol min Share with your friends Share 0 Garima Chaudhary answered this Dear student, H2O2 → H2O + 1/2 O2 Rate constant fo the first order reaction is : k = 1tlna0atk = 150ln0.50.125k = 150ln 4 min-1 rate of disappearance of H2O2 = rate of appearance of O21/2rO2 = 12 rH2O2 = 12k [H2O2] = 12×150× ln 4 × 0.05 = 6.9 × 10-4M min-1 Regards 31 View Full Answer
