Please explain in detail.
Please explain in detail. 56. Solid ammonium cynide decompose in to NH3(g) & HCN (g) reversibly. The two gases are in equimolar ratio at all moments. If K, for e NH, (g)+HCN(g) is 4 atm. The increase in moles of ammonia due to decomposition is 33.3% then maximum amount of solid decomposed is-. (a) V/RT moles (b) 2V/RT moles (c) V/3RT moles (d) 3V/RT moles (V-volume of container & T-temperature).

Dear Student,

{NH}_{4} CN (s) \leftrightarrow {NH}_{3} (g) + HCN (g) C 0 0 C (1 - α) Cα Cα K_{c} = \frac{{Cα}^{2}}{(1 - α)} and, α = 0.333 K_{c} = \frac{C (0.333)^{2}}{(1 - 0.333)} and, K_{p} = K_{c} (RT)^{∆ n} ∆ n = 2 - 0 = 2 so, K_{c} = \frac{4}{(RT)^{2}} i . e . \frac{4}{(RT)^{2}} = \frac{C (0.333)^{2}}{(1 - 0.333)} or, C = \frac{24.08}{(RT)^{2}} So, Cα = \frac{8}{(RT)^{2}}