PLEASE EXPLAIN ME IN DETAIL THE CONCEPT OF CALCULATION OF "N- FACTOR" AND EQUIVALENT WEIGHT FOR INTRAMOLECULAR , INTERMOLECULAR AND - Chemistry - Redox reactions

Question

PLEASE EXPLAIN ME IN DETAIL THE CONCEPT OF
CALCULATION OF
"N- FACTOR" AND
EQUIVALENT WEIGHT FOR
INTRAMOLECULAR , INTERMOLECULAR AND DISPROPORTIONATION REACTION IN
REDOX REACTION PLEASE EXPLAIN IT WITH ENOUGH EXAMPLES

Vartika Jain · Accepted Answer

Dear Student,

n-factor = number of electrons transferredand, Equivalent weight=Molar massn-factorIntermolecular redox reactions are those reactions where one substance is oxidised while the other is reduced
 For eg
 2Al + Fe2O3 → Al2O3 + 2Fe               0         (+3)         (+3)        0Here, Al gets oxidised and Fe is getting reduced
Fe3+ + 3e- → FeAl→ Al3+ + 3e-n-factor(Fe3+)= 3n-factor (Al3+)=3Equivalent weight of Fe2O3=Molar mass of Fe2O33Equivalent weight of Al2O3=Molar mass of Al2O33Intramolecular redox reactions are the reactions where one element of a compound is oxidised while the other is reduced
For eg
 KClO3 →∆ KCl + 32O2Here Cl is reduced from +5 to -1and O is oxidised from -6 to 0Now, Cl+5 + 6e- → Cl-O3-6 → O20 + 6e-n-factor= 6 as 6 electrons are transferredEquivalent weight of KClO3= Molar mass of KClO36Disproportionate redox reactions are the reactions where a same element present in a particular compound is oxidised as well as reduced simultaneously
For eg
 2Na2S2O3 + I2 → 2NaI + Na2S4O6Here, S is getting dispropotionate
Sulphur changes its oxidation state from +2 to +2
5Change in oxidation state per molecule = 0
5×2=1So, n=1Equivalent weight of Na2S2O3=Molar mass of Na2S2O31Equivalent weight of Na2S4O6=Molar mass of Na2S4O61

PLEASE EXPLAIN ME IN DETAIL THE CONCEPT OF CALCULATION OF "N- FACTOR" AND EQUIVALENT WEIGHT FOR INTRAMOLECULAR , INTERMOLECULAR AND DISPROPORTIONATION REACTION IN REDOX REACTION. PLEASE EXPLAIN IT WITH ENOUGH EXAMPLES