Please explain the basic strength order of the 2nd question-

Please explain the basic strength order of the 2nd question- 13. Arrange the following in decreasing order of their basic strength (A) (l) CH30Na (II) (CH3)2Ne (Ill) (II) CH3NHNa (Ill) CH3COONa (IV) CHO IV)CH3Na

Dear Student,

This question can be solved by finding out the acidic strength of the conjugate acids of the given compounds.

The given compounds are salts.
Their conjugate acids are:

CH₃ONa = CH₃OH
CH₃NHNa = CH₃NH₂
CH₃COONa = CH₃COOH
CH₃Na = CH₄

Now, alkane is the weakest acid. Amine is stronger than alkane but weaker than alcohol. Alcohol is a weaker acid than carboxylic acid.

So, the increasing order of acidic strength of the conjugate acids is:
CH₄ < CH₃NH₂ <CH₃OH < CH₃COOH

The weaker the conjugate acid, the stronger is the base.
The stronger the conjugate acid, the weaker is the base.

So, the decreasng order of basic strength is:

CH₃Na > CH₃NHNa > CH₃ONa > CH₃COONa

Hope this information will clear your doubts about this topic.

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