Please help me expert ASAP

Solution 
The voltage is 2V so both the ions i.e., Ag⁺ and Au⁺ will be reduced.
Also, as both the ions are univalent, so their equal gram equivalent weight will be reduced, that can be calculated as follows:
$\begin{array}{rcl}\frac{\mathrm{Weight} \mathrm{of} \mathrm{Ag}}{\mathrm{Equivalent} \mathrm{Weight} \mathrm{of} \mathrm{Ag}}& =& \frac{\mathrm{Weight} \mathrm{of} \mathrm{Au}}{\mathrm{Equivalent} \mathrm{Weight} \mathrm{of} \mathrm{Au}}\\ \frac{\mathrm{Weight} \mathrm{of} \mathrm{Ag}}{\mathrm{Weight} \mathrm{of} \mathrm{Au}}& =& \frac{\mathrm{Equivalent} \mathrm{Weight} \mathrm{of} \mathrm{Ag}}{\mathrm{Equivalent} \mathrm{Weight} \mathrm{of} \mathrm{Au}}\\ & =& \frac{\mathrm{Atomic} \mathrm{weight} \mathrm{of} \mathrm{Ag}}{\mathrm{Atomic} \mathrm{weight} \mathrm{of} \mathrm{Au}}\end{array}$
Therefore, both silver and gold will be electrodeposited in proportion to their atomic masses respectively.