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Please help me out with this

Please help me out with this 18. A packet of weight W is dropped with the help of a parachute and on striking the ground comes to rest with a retardation equal to twice the acceleration due to gravity. What is the force exerted on the ground? (b) 2W

2W. Because

Force exerted is equal to the change in momentum in one second. Now, retardation is rate of decrease of velocity. The value of retardation is given as 2g. Then,

Force, F=dp/dt=m(dv/dt). But,

m=W/g and dv/dt=2g, therefore ,

F=(W/g)(2g)=2W

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