# Please solve part 4:

The answer to part (i) is given below:

|x^2 - 7x + 10|

finding the zeroes of the equation, we have:

x^2 - 7x + 10 = 0

or, x^2 - 2x - 5x + 10 = 0

or, x(x-2) -5(x-2) = 0

or, (x - 2)(x - 5) = 0

Therefore, at x = 2 and x = 5, the equation intercepts x axis, and the value is negative in between 2 and 5.

Therefore, the equation should be represented as,

**x^2 - 7x + 10 for x<2**

x^2 -7x +10 for x>5

x^2 -7x +10 for x>5

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I hope you understood the solution

Regards

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