Please solve part 4:

(iv) $\left|x^2-6x+10\right|$

Dear Student,

The answer to part (i) is given below:

|x^2 - 7x + 10| 

finding the zeroes of the equation, we have:

x^2 - 7x + 10 = 0
or, x^2 - 2x - 5x + 10 = 0
or, x(x-2) -5(x-2) = 0
or, (x - 2)(x - 5) = 0

​​​​​​Therefore, at x = 2 and x = 5, the equation intercepts x axis, and the value is negative in between 2 and 5.



Therefore, the equation should be represented as,

x^2 - 7x + 10 for x<2
x^2 -7x +10 for x>5

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​​​​ ​I hope you understood the solution

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