# Please solve question no 29

We have,
Molar concentration= partial pressure x henry constant
Hence, C = p xK​h​
Or, n/V =p xK​h​
Or, n =p xK​h​  xV
'Putting the values we get, no. of moles of oxygen gas as:
$n=0.5atmx0.1Lx1.4x10-3mol/atmL=0.00007$
Thus, 1 mole of oxygen gass= 32 g
Hence, 35.7 mole of oxygen gas = 0.00007x 32=2.24 x10-3 g = 2.24mg
Correct answer is d). 2.24 mg

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