Pleass give solution for que 26

Solution:
Given R2 = P2 + Q + 2PQcosθ .... equation 1

now when magnitude of q is doubled it makes 900 with the P vector

solution

So as we know the angle between the vectors are :

Tan θ = Bsinθ/(A+Bcosθ)  Tan 90o = 2Qsinθ/(P+2Qcosθ) .  As Tan 90o = infinity  so,  P+2Qcosθ=  0 or cosθ = -P/2Q... equation 2  substituting in equation 1  we have:   R2 = P2 + Q2  + 2PQ(-P/2Q)   R2 = P2 + Q2  - P2  or,  R2 =  Q2   or , R = Q

 

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