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Q.7. A closed vessel containing N 2 O 4 gas is maintained at temperature of 298 K at 1 atm pressure is heated to 500 K. At this temperature 45 % by weight of N 2 O 4 decomposes to N O 2 . What will be the final pressure of the gaseous mixture at 500 K?
A. 2.4 atm
B. 2.6 atm
C. 2.8 atm
D. 3.0 atm

Dear Student,
                         let n mole of N2O4  is presant there after dissociation .55n of N2 O4 will be and .9n of NO2Intially PV=nRTVn=R×2981=298Rafter dissociation PfV=(.55+.9)nR×500Pf=1.45298×500=2.43=2.4atm
Regards

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