Pls find the domain and range of the function given in the pic. Also draw its graph. Share with your friends Share 1 Neha Sethi answered this Dear student We have, fx=1-x2⇒1-x2≥0 ∵fx⇒f(x)≥0⇒-1≤x≤1⇒x∈-1,1Domain of f:x∈-1,1Range of f Let y =fx then y=1-x2⇒y2=1-x2⇒x=1-y2Clearly , x will take real values if 1-y2≥0⇒y2-1≤0⇒y-1y+1≤0⇒-1≤y≤1⇒y∈-1,1Also y=1-x2≥0 for all x∈-1,1So , y∈0,1 for all x∈-1,1Hence Range of f=0,1 Regards 1 View Full Answer