Pls help me with this
Dear student,
Oxidation of Cobalt is +3, it has 3 unpaired electrons in 3d7 orbital and a pair of electrons in 4s2 orbital.
Oxidation of Cobalt is +3, it has 3 unpaired electrons in 3d7 orbital and a pair of electrons in 4s2 orbital.
Co+3 loses one electron from 3d orbital and one electron from 4s orbital.
When oxalate ions approach cobalt ion pairing of electrons takes place in the 3d orbital.
Thus the resulting hybridized orbital is d2sp3.
It is an exception of CFT and cannot be explained on the basis of theory. The reason for it to form 6 hybridized orbitals
can be due to the celate effect of oxalate ion which increases CFSE and results in the pairing of t2g orbitals. Thud 2 d, 1 s and 3 p orbitals are available for hybridization.
Hope this helps.
Regards.
It is an exception of CFT and cannot be explained on the basis of theory. The reason for it to form 6 hybridized orbitals
can be due to the celate effect of oxalate ion which increases CFSE and results in the pairing of t2g orbitals. Thud 2 d, 1 s and 3 p orbitals are available for hybridization.
Hope this helps.
Regards.