Pls solve fast and the diagram for this question is the second one.
Q.(b) In figure (ii) given below, ABCD is a quadrilateral in which AB = AD, A = 90 ° = C , BC = 8 cm and CD = 6 cm. Find AB and calculate the area of ABD.


In right angle triangle BCD,Using pythagorus theorem,  BD2= BC2+CD2BD=  BC2+CD2=36+64=10 cm Now in right angle traingle ABD, Using pythagorus theorem,  AB2+AD2=BD2now since AD=AB2AB2= 100AB= 52 cm area of triangle ABD = 12×AB×AD=AB22=25 cm2


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