pls solve QUESTION number 6 . ....explain me the QUESTION as well as the answer with detailed steps... Question No. 6 A student was performing a titration experiment with 15 mL of hydrazine sulphate solution and ferric chloride solution. During the reaction, ferric ions were reduced to ferrous ions and were estimated with the help of 0.02 M K M n O 4 . The volume of K M n O 4 solution used by ferrous ions was 30 mL. Find the amount of hydrazine sulphate present in 1 L of solution. A. 5.3 g B. 6.5 g C. 7.0 g D. 8.2 g Share with your friends Share 0 Manasa Hegde answered this Dear Student, 30ml of 0.02M KMnO4 is required to reduce 15ml of M1 concentration of hydrazine sulphateM1V1=M2V2M1X15ml = 0.02M X 30mlM1=0.04Mthe molarity of hydrazine sulphate is 0.04MM = moles of solutevolume of the solutionmoles of solute = molarity x volume of solutionmoles of solute = 0.04M x 1L = 0.04 molesmass of hydrazine sulphate = no. of moles of hydrazine sulphate x molar masschemical formula of hydrazine sulphate is H6N2O4S = (1X6)+(14X2)+(16X4)+32mass of hydrazine sulphate =0.04 x 130 = 5.2gtherefore the answer is option 'a' Regards, 0 View Full Answer Harshita Rastogi answered this It seems difficult. Such type of questions come only in iit jee bu t not in neet. 1
