Dear Student,y=x2-x-6x-3dydx=(x-3)ddx(x2-x-6)-(x2-x-6)ddx(x-3)(x-3)2dydx=(x-3)(2x-1)-(x2-x-6)(1)(x-3)2dydx=2x2-x-6x+3-x2+x+6(x-3)2dydx=x2-6x+9(x-3)2dydx=(x-3)2(x-3)2dydx=1Option 3 is correctRegards

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D e a r S t u d e n t, y = \frac{x^{2} - x - 6}{x - 3} \frac{d y}{d x} = \frac{(x - 3) \frac{d}{d x} (x^{2} - x - 6) - (x^{2} - x - 6) \frac{d}{d x} (x - 3)}{{(x - 3)}^{2}} \frac{d y}{d x} = \frac{(x - 3) (2 x - 1) - (x^{2} - x - 6) (1)}{{(x - 3)}^{2}} \frac{d y}{d x} = \frac{2 x^{2} - x - 6 x + 3 - x^{2} + x + 6}{{(x - 3)}^{2}} \frac{d y}{d x} = \frac{x^{2} - 6 x + 9}{{(x - 3)}^{2}} \frac{d y}{d x} = \frac{{(x - 3)}^{2}}{{(x - 3)}^{2}} \frac{d y}{d x} = 1 O p t i o n 3 i s c o r r e c t R e g a r d s

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