Plz explain.q.23 . How to determine whether central.atom show 4.or 6 oxidation number
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Please find the solution to the asked query:
Hence option A is correct.
[To know whether the complex formed will be tetrahedral, octahedral or square planar, we need to take the ions and ligands into consideration, then the splitting diagram is formed to know how many electrons will pair up under the influence of the ligands, this will give the hybridisation and hence the geometry.
You will study these in details in higher classes ]
Hope this information will clear your doubts regarding the topic. If you have any other doubts please ask here on the forum and our experts will try to solve them as soon as possible.
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Please find the solution to the asked query:
| Metal ion | complex with ammonia | Geometry |
| Ni2+ | [Ni(NH3)6]2+ | Octahedral |
| Pt2+ | [Pt(NH3)4]2+ | Square planar |
| Zn2+ | [Zn(NH3)4]2+ | Tetrahedral |
Hence option A is correct.
[To know whether the complex formed will be tetrahedral, octahedral or square planar, we need to take the ions and ligands into consideration, then the splitting diagram is formed to know how many electrons will pair up under the influence of the ligands, this will give the hybridisation and hence the geometry.
You will study these in details in higher classes ]
Hope this information will clear your doubts regarding the topic. If you have any other doubts please ask here on the forum and our experts will try to solve them as soon as possible.
Regards