Plz explain the circled part

Plz explain the circled part a a' MOK O,07s-' respectively. Calculate values of E, and A. log = 2.303R log — 002 - 700 x 500 x 5.714 E. 0.344 19.15/3.714 x 18230.8 J A • 002/0.012

Dear student,

In the given equation of activation energy:

k = A e^{- \frac{E_{a}}{R T}}

Substitute the given values of Activation energy, gas constant and temperature.

k = A e^{- \frac{18230.2 J}{8.314 J K^{- 1} m o l^{- 1} \times 500 K}}

e^{- \frac{18230.2 J}{8.314 J K^{- 1} m o l^{- 1} \times 500 K}} = 0.012

A = \frac{0.12}{0.012} = 1.61

Regards.

Hope this solution helps you.