Plz provide the answer quickly Share with your friends Share 0 Chirag Gupta answered this Dear StudentMolecular formula of pure compound with Cu+ ion is Cu2S.Due to impurity of Cu2+ ion, molecular formula becomes Cu1.8S.Total loss of Copper =2−1.8=0.2mol % of Cu2+ in total copper content = 0.21.8×100=11.11% Mole percentage of Cu2+ in total copper content is 11.11%Option 2 is correct.Regards 1 View Full Answer