Plz solve q. No. 67

In this question I used the faraday's law formula n*nfactor=Q/F
But with that formula and taking nfactor as 2 I am not getting the answer

Kindly clarify it.

Solution:At anode: 2H2O(l) O2(g)+4H(aq)++4enf for O2=4t= 9.65 min = 9.65×60 secI = 1AnO2=I×tnf×96500=1×(9.65×60)4×96500=0.0015 molVO2 at STP =0.0015 ×22400=33.6ml

Option A is correct

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