Q-15 : A uniform rod of length l =6 m and mass 'm' rests on a frictionless horizontal ground surface . A point mass ' m' moving horizontally at right angles to rod with initial velocity vo=10 m/s collides with one end of the rod and sticks to it . The angular speed of (rod+ particle ) system just after collision is x rad/sec. Find the value of x Share with your friends Share 0 Deepak Kumar answered this Dear Student Since there is no external force so linear momentum and angular momentum will remain conservedmv=mωL2+2mv1v=ωL2+2v1v1=v2-ωL4---(1)conservation of angular momentum mvL2=mωL2L2+IωmvL2=mωL2L2+2mL212ωv=ωL2+ωL3v=5ωL6ω=6v5Lnow in the question given that v=10m/s and L=6m ω=6×105×6=2 rad/sec Regards -1 View Full Answer
