Q. Consider the situation shown in figure. Initially the spring is unstretched when the system is released from rest. Assuming no friction in the pulley, the maximum elongation of the spring is Share with your friends Share 1 Shobhit Mittal answered this Dear Student, let the mass m get down by height h and stop .this loss in potential enrgy will store in PE of the spring since if the block moves h down then spring also stretch by length h mgh=kh22h=2mgk maximum elongation .Regards -1 View Full Answer