Q no 2 2 A ball is thrown from the roof of a building of height - Physics -

Question

Q no 2

2 A ball is thrown from the roof of a building of
height 44m with speed 40 at the angle θ below the
horizontal it lands 2 seconds later at a point 30m from the base of
the building, then the value of tan θ is : (g=10
m/s2)

A   4 5              
    B   3 5          
              C   5 4
                  D
  5 3

Vijay Shankar Yadav · Accepted Answer

Dear Student,
It is making angle θ below with horizontal so horizontal velocity =V0cos(θ)and vertical velocity =V0sin(θ) (down ward direction)so according to question 44=V0sin(θ)×2+12×10×2212=V0sin(θ)------1and V0cos(θ)×2=30or 15=V0cos(θ)----2now divide equation 1 by equation 2 we gettan(θ)=45
Regard

Q no. 2 2. A ball is thrown from the roof of a building of height 44m with speed 40 at the angle θ below the horizontal. it lands 2 seconds later at a point 30m from the base of the building, then the value of tan θ is : (g=10 m/s2) A 4 5 B 3 5 C 5 4 D 5 3