Q) The diameter of a wire measured by a screw gauge is given by 1.012cm, 1.015cm, 1.018cm,1.013cm, 1.017cm respectively. Find the diameter of the wire,mean absolute error and percentage error. Share with your friends Share 2 Mohammed Naved answered this Dear Student (i) Diameter of wire= 1.012+1.015+1.018+1.013+1.0175 = 5.0755 = 1.015 cm(ii) Mean Absolute ErrorAbsolute Error for each measurement∆ x1 = |1.012-0.015| = 0.003 cm∆ x2 = |1.015-0.015| = 0.000 cm∆ x3 = |1.018-0.015| = 0.003 cm∆ x4 = |1.013-0.015| = 0.002 cm∆ x5 = |1.017-0.015| = 0.002 cmso, Mean Absolute Error = 0.003+0+0.003+0.002+0.0025=0.0105= 0.002 cm(iii) Percentage Error= Mean Absolue ErrorMean Value of Diameter ×100= 0.0021.015×100 = 0.197 % Regards 8 View Full Answer
