Q. The velocities of two steel balls before impact are shown. If after head on impact the velocity of ball B is observed to be 3 m/s to the right, the coefficient of restitution is- 

dear student 
apply conservation of momentum before and after the collisioninitial momentum = m1u1+m2u2here m1=0.6 m2 = 0.4 u1=4 u2=-2 initial momentum = 0.6*4-0.4*2 =1.6 final velocity of mass b = 3m/s final momentum = 0.4*3+0.6*v2 as initial momentm = final momentum 1.6=1.2+ .6v2 which gives v2= 2/3as e=velocity of separationvelocity of approch =3-2/36=7/18 answer   

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