Q1. Ans: option B. Can you show pls? Share with your friends Share 0 Bakul Biswas answered this Dear Student , Let axis of rotation pass through hypotenuse. considering rotation about hypotenuse you will see that it will make a square joining two triangles and hypotenuse will be the diagonal of the square. we know moment of inertia of the diagonal near to the axis of the square=Ml26Now mass of square is M .now mass of the triangle will be half of the mass of the square . So moment of inertia about hypotenuse =Ml212 Now applying perpendicular axis theorem moment of inertia about base as well as perpendicular is=32× Ml212=Ml28 . Regards 1 View Full Answer
