Q36 36 0 05 Faraday charge is passed in 100 ml, 0 1 M NaCl solution - Chemistry - Electrochemistry

Question

Q36

36 0 05 Faraday charge is passed in 100 ml, 0 1 M
NaCl solution Calculate the final pOH of the solution Assume volume
remains constant

Vartika Jain · Accepted Answer

Dear Student,

In electrolysis of NaCl solution, reaction taking place ar cathode is H2O(l) + 2e- → H2(g) + 2OH-So, 2F of electrons gives 2 mol of OH-0
05 F of electrons will give 22×0
05=0
05 mol of OH-pOH = -log [OH-]         =-log (0
05)         =-(-1
30)         =1 30

Q36 36. 0.05 Faraday charge is passed in 100 ml, 0.1 M NaCl solution. Calculate the final pOH of the solution. Assume volume remains constant.

Q36

36. 0.05 Faraday charge is passed in 100 ml, 0.1 M NaCl solution. Calculate the final pOH of the solution. Assume volume remains constant.