Q6: 6. A Weightless inextensible rope rests on a stationary wedge forming an angle α with the horizontal. One end of the rope is fixed to the wall at point A. A small load is attached to the rope at point B, The wedge starts moving to the right with a constant acceleration a. The magnitude of acceleration of the load is given by: A a B 2 a sin a 2 C a sin α D g sin α Share with your friends Share 17 Sanjay Singh answered this Dear student Putting the dot product of acceeration and the tension in the thread equal to zero at the pulley and at the load.-T×a+T×(acosα)+T×a1=0T(-a+acosα+a1)=0 (a1: is acceleration of the load with respect to ground along the plane)As T is not zero so-a+acosα+a1=0a1=a-acosαAs the load is in contact with the wedge so acceleration of wedge and the load in direction perpendicular to the plane of the wedge must be same.a2=asinαNow net acceleration of the load is A=a21+a22=(a-acosα)2+a2sin2α=a1+cos2α-2cosα+sin2α=2-2cosα=2(1-cosα)=2×2sin2α2=2sinα2Regards -9 View Full Answer