Dear student, Initially, Ei = - GMe m/4Re Finally, Ef = - GMe m/8Re ΔE = Ef – Ei = gmRe/8 = 3 13 109 J The kinetic energy is reduced and it mimics ΔE, namely, ΔK = Kf – Ki = – 3 13 × 109 J The change in potential energy is twice the change in the total energy, namely ΔV = Vf – Vi = – 6 25 × 109J â€‹â€‹â€‹â€‹â€‹â€‹â€‹Regards

Qsn no 45.

Qsn no 45. 0.2-109 A 400 kg earth sate illite is to an orbil of radius to an orbit of radius AR. Kind the energy required to in and the change in PE of the satellite in this transfer. What is the binding energy of a satellite of mass 200 kg •nos ing in a orbit around earlh close to its surface and a height of60() kilt? G 6.67 v 10 SI units: Radiusofearlh 6400 ktn: Mass of earth energy ofa satellite is J Calculate its KE and PF. (4 x J; -8X10• J) 49. . Find the total energy and binding ofan artificial satellite of mass 801) kg orbiting at a height of 1800 km above the surface of the earth. [G = 6.67K 10 Sl units; Radius Of 6400 km: Mass or earth 610-4 kg I (-1.952 J; 1.9S2XlO'O J) Find he escape velocity for a 2000 kg body from the earth's surlåce and the the body musl have to overcome the earth •s gravitational field. [G 6.6710 Sl units: Radius of earth 6.4 m; Mass of carth kg] (11.18 km/s; 6.25x10'OJ)

Dear student,
Initially, Ei = - GMe m/4R_e
Finally,
Ef = - GMe m/8R_e
ΔE = Ef – Ei = gmR_e/8
= 3.13 10⁹ J
The kinetic energy is reduced and it mimics ΔE, namely, ΔK = Kf – Ki = – 3.13 × 10⁹ J.
The change in potential energy is twice the change in the total energy, namely ΔV = Vf – Vi = – 6.25 × 10⁹J
Regards

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