Show that the middle term in the expansion of (1+x)2n is-1 3 5 (2n-1)/n! 2nxn ,where n is - Maths - Binomial Theorem

Question

Show that the middle term in the expansion of (1+x)2n
is-1 3 5 (2n-1)/n! 2nxn ,where n is a positive integer
Here n is even so the middle term is (n+1) th term So the n+1 th
term is 2n Cn a2n-n bn
i e 2n Cn 12n-n xn i e
2n Cn xn I'm i correct till this
step???

Brijendra P. · Accepted Answer

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Show that the middle term in the expansion of (1+x)2n is-1.3.5...(2n-1)/n! 2nxn ,where n is a positive integer.Here n is even so the middle term is (n+1) th term.So the n+1 th term is 2n Cn a2n-n bn i.e 2n Cn 12n-n xn i.e 2n Cn xn .I'm i correct till this step???

Show that the middle term in the expansion of (1+x)²ⁿ is-1.3.5...(2n-1)/n! 2nxⁿ ,where n is a positive integer.Here n is even so the middle term is (n+1) th term.So the n+1 th term is ²ⁿ C_n a^2n-n bⁿ i.e ²ⁿ C_n 1^2n-n xⁿ i.e ²ⁿ C_n xⁿ .I'm i correct till this step???