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Sodium crystallizes in a BCC unit cell. Calculate the approximate no. of unit cell in 9.2 gm of sodium?

 Sodium Crystallises in a body centered cubic unit cell.What is the approximate number of unit cells in 23 gm of Sodium ? (Atomic mass of Sodium =23)

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no. of atoms per unit cell for bcc = 2

no. of atoms in 9.2 gm of Na = 9.2/23 x 6.022 x 1023 = 2.4088 x 1023

no. of unit cell = 2.4088 x 1023 / 2 =1.2044 x 1023

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Given m = 9.2 g, n= m/M = 9.2 g/ 23 g mol-1= 0.4 mol

N = nNA = 0.4 mol X 6.022X 1023 mol-1 = 2.4088X1023

Since For BBC, Z=2 i.e. no. of atoms per unit cell for bcc = 2

2 Na atoms contains = 1 unit cell

2.4088 x 1023 Na atoms contains = 2.4088 x 1023 / 2 =1.2044 x 1023 unit cells

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the answer is given above XD
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1.2044 × 10^23
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No of atoms per unit cell for bcc =2
No of atoms in 9.2gm of Na=9.223×6.022×1023=2.4088×1023
No of unit cell =2.4088×10232
=1.2044×1023
                            ANSWERED BY SANJIB MALAKAR ;FROM HAILAKANDI
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no. of atoms per unit cell for bcc = 2 no. of atoms in 9.2 gm of Na = 9.2/23 x 6.022 x 1023 = 2.4088 x 1023 no. of unit cell = 2.4088 x 1023 / 2 =1.2044 x 1023
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Here is the answer

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