Solve 4 plzz
4. The total number of octahedral void(s) per atom present in a cubic close packed structure is:
(a) 1
(b) 2
(c) 4
(d) 3
Dear Student, In a ccp arrangement, Total number of octahedral voids= Effetive number of atoms. In ccp 4 effective atoms are present so octahedral voids are 4. So, 1 octahedral void per atom . Correct answer is (a). Regards,