Solve question 12



12. What will be the minimum angle of incident such that the total internal reflection occurs on both the surfaces ?

Dear Student ,
For the first surface , 

2sini1=2 sin90°i1=45°Critical angle for the first surface is 45°.For second surface ,2 sini2=3 sin90°i2=60°So the critical angl efor the second surface is 60° .Therefore  the minimum angl eof incidence =60° .Regards

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